$\left(7x^3\right)^2\left(x^8\right)^{\frac{1}{2}}$
$\frac{1}{2}\cdot\left|-4\right|-1$
$e^{2x}\frac{dy}{dx}=y-ye^{3x};\:y\left(0\right)=1$
$-x^2-2x+6$
$7<5-x$
$8^2-16$
$a=\frac{1}{2}b$
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