$\left(\frac{8x^3y^{-2}x^4}{4x^{-2}y^4z^{-3}}\right)^{-2}$
$-6x+9<-2x+8$
$\lim_{x\to2}\left(\frac{x^2-6x+8}{x-4}\right)$
$11+\left(-5\right)\cdot6$
$\int x^3\sqrt{x+7}dx$
$x^2-+18x+-9$
$\lim_{x\to0}\left(\frac{x-tan\left(x\right)}{x-sec\left(x\right)}\right)$
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