$\left(4x+1\right)^2+\left(4x-3\right)^2-16x\left(2x-1\right)$
$\left(30+5d^3\right)^2$
$7^5\:x\:7^{-2}$
$1-128^7$
$\:\left(7x-3\right)\left(7x+3\right)$
$\left(3\cdot\tan^2x-1\right)\left(\tan\left(x\right)-1\right)=0$
$x^3-3x^2-144x-140$
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