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Exercise

$\frac{d}{dx}x^3y^2-x^3y+4xy^3=0$

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Final answer to the exercise

$y^{\prime}=\frac{-3x^{2}y^2+3x^{2}y-4y^3-12xy^{\left(2+{\prime}\right)}}{\left(2y-1\right)x^{3}}$

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  • Integrate by partial fractions
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