$36f^4-64$
$x\left(\frac{\pi}{2}\right)=0\:$
$v^2+12vu+36u^2$
$\left(2\cdot n+1\right)^2$
$\sqrt[3]{12a^5}b^{7c}$
$\frac{x^4+3x^2-8-2}{x-2}$
$\frac{x^2-5x+8}{x+3}$
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