$x^2+6x\le0$

$y^{'''}-4y^{''}-5y^'=0$

$\tan\left(0\right)=\frac{\sin\left(0^{\circ}\right)}{\cos\left(0^{\circ}\right)}$

$\log_y\left(y^5\right)+\log_y\left(y^6\right)$

$\:x^2+2\sqrt[3]{x}-5y+7=0$

$sec\left(x\right)+tan\left(x\right)=\left(1-sin\left(x\right)\right)sec\left(x\right)$

$\lim_{x\to\infty}\left(\frac{\left(8y+x\right)-\left(8y\right)}{x}\right)$