$\left(4x+3x^2\right)^2$
$\frac{x^3\:-\:8}{x-2}$
$n^2-n-12$
$\frac{12x}{x+3}>x+3$
$\frac{6d^6}{3d^3}$
$\frac{4}{9}x^2-\frac{24}{9}x+12$
$\frac{11}{12}-\:\frac{1}{6}q+\frac{5}{6}6q-\frac{1}{3}$
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