$\left(\frac{1}{6}a^5\right)\left(-3a^2\right)\left(4a^7\right)$

$x^3-1>0$

$\frac{-x^4+10x^2+2x-2}{x+3}$

$n^2+3n-10=0$

$\frac{dy}{dx}=\frac{3x+1}{x+1}$

$\frac{1}{3}e^x+\frac{10}{3}e^{-2x}+\left(\frac{2}{3}e^x-\frac{10}{3}e^{-2x}\right)$

$\lim_{x\to5}\left(x^2+4x\right)$