$\int6sec^3\left(x\right)dx$
$\sec\:^2\left(x\right)+\tan\:^2\left(x\right)\sec\:^2\left(x\right)$
$\left(3a-4b^2\right)^5$
$\left(7-3\right)\left(4+4\right)$
$2x^3.\:-5x^4$
$5-23-\left(-27\right)$
$\left(7-3i\right)-\left(3-7i\right)$
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