$\left(x+6\right)^2=64$
$\left(3ab^2+5ax^3\right)^2$
$\int x\left(x^3-2\right)dx$
$\left(-xy+5a^3b^6c\right)\left(+10mn-3m^4\right)$
$\frac{\sin\left(a\right)}{\tan\left(a\right)}=\cos\left(a\right)$
$169m^4-196n^8$
$-7+5x=23$
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