$\frac{dy}{dx}=ln\left(\sqrt[5]{x^3}\right)$
$2y^2-7y+5$
$\left(9+x^8\right)\frac{dy}{dx}=\frac{x^7}{y}.$
$\left(2m^2-10y\right)\left(2m^2+10\right)$
$x+3x^2$
$49b^2-56=16$
$3x\:+\:2y\:+\:z\:=\:7\:$
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