$1x^2-5x+6$
$8a^{12}-b^3$
$\int_{-\infty}^1\left(\frac{1}{x^2}\right)dx$
$\:\left(3x^3+4x^2-7x+1\right)+\left(9x^3-4x^2-6x\right)$
$x^{2}-16x+4$
$\left(x\cdot2\right)\cdot\left(x+3\right)$
$\left(x+6\right)\left(x+2\right)\left(x+3\right)$
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