$-25^2$
$\left(8y\:+\:4\right)\left(8y\:+\:4\right)$
$\frac{d^3y}{dx^3}\left(\left(3x+5\right)^3\right)$
$2x\:-\:4\:+\:3\:-\:3x$
$-1,348-\left(-282\right)$
$8^0+6^0-17^1$
$6x+31=55$
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