$\int\frac{\left(lnx\right)^2+1}{x}dx$
$\int e^{3x+8}dx$
$\lim_{x\to2}\left(\frac{x^2-6x+10}{x-1}\right)$
$12\cdot\left(15\right)\cdot\left(4\right)\cdot\:\left(3\right)\:\:$
$\int\frac{2x+5}{\left(3x^2+15x\right)^3}dx$
$4\left(x-5\right)-6x=20-3\left(2x+4\right)$
$x^2=x+9$
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