$\frac{p}{15}-2<-1$
$\frac{1+tan}{1+cos}=\frac{sin}{cos}$
$\left(x+2\right)^3\left(x-3\right)^3$
$\frac{d}{dx}\left(\sqrt[4]{4x-1}\right)$
$x\left(5x+15\right)$
$\frac{1}{2}\:y\:1$
$x''-x'=0$
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