$4x^2+16x+4$
$\lim_{x\to\infty}\left(\frac{arctan\left(x^2\right)}{x^5}\right)$
$2x\:-\:\left(-x-12\right)+\:3x\:-\:7$
$11\left(-6n\right)$
$2x^5+5x^3-12x^2+10x-5$
$n^2+3n=10$
$\lim_{x\to0}\left(x^2ln\left(x\right)\right)$
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