$\left(\frac{1}{2}x+\frac{4}{3}\right)^2$

$\left(8-4+3\right)-\left(5-9\right)-6+7$

$\frac{5}{7}\int\frac{4}{ut-7}\:\:\:\:dt$

$\int\frac{\sqrt{6}+\tan\left(x\right)}{\cos^{2}x}dx$

$\left(10-15\right)+3\cdot\left[3-\left(2+1\right)\right]$

$1+\cos+\sin^2x$

$\frac{x}{2}\ge4-6x$