$4\left(x+1\right)^2+8\left(x+1\right)+3$
$\sqrt[4]{256a^{8}b^{12}c^{16}}$
$-1\frac{2}{3}x\:4\frac{3}{4}$
$\frac{d^2}{dx^2}\left(fg\right)$
$\left(\frac{2}{b}\right)\left(\frac{1}{2}\right)$
$\frac{dy}{dx}=ax^3$
$\left(7^3\right).7:7^2$
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