$$\frac{-p}{p}$$

$$t^2\cdot\frac{dx}{dt}+5tx=t^3\cdot ln\left(t\right)+4$$

$$125-v^3$$

$$3x^2-15$$

$$\frac{2a\cdot\left(4b+6c\right)}{\left(6c-2a\right)\cdot2a}$$

$$\frac{x^3-2x^2+31x+20}{x+5}$$

$$\int\frac{9^{2x+5}}{3}dx$$