$\frac{d}{dx}\:\frac{2}{4-3x}$
$x^4\:-\:3x^3\:-\:4x^2\:+\:12x\:=\:0$
$9+6b^6+b^{12}$
$\frac{1.3333\:+0.1}{0.0303030}-\frac{3}{10}$
$\left(2-t\right)\left(2+t\right)$
$-10g+5g^2+-7g-10g+-6g^2+-5$
$x^2+2\left(x\right)+16=0$
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