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f(x)=(2x^2+4x+-3)^5(2x^3-2x^22x+-2)^3−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

ddx(2x2+4x−3)5(2x3−2x2+2x−2)3\frac{d}{dx}\left(2x^2+4x-3\right)^5\left(2x^3-2x^2+2x-2\right)^3

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Final answer to the exercise

5(2x2+4x−3)4(4x+4)(2x3−2x2+2x−2)3+3(2x2+4x−3)5(2x3−2x2+2x−2)2(6x2−4x+2)5\left(2x^2+4x-3\right)^{4}\left(4x+4\right)\left(2x^3-2x^2+2x-2\right)^3+3\left(2x^2+4x-3\right)^5\left(2x^3-2x^2+2x-2\right)^{2}\left(6x^{2}-4x+2\right)

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ddx (2x2+4x−3)5(2x3−2x2+2x−2)3
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