$\frac{5}{x+4}=\frac{2}{x-2}$
$\left(3-x^3\right)^2$
$4p+4=p^2+4p+3$
$\int tan3\left(x\right)\sqrt{s}ec\left(x\right)dx$
$\left(\frac{1}{2}a^3\cdot\frac{1}{2}\right)^2$
$\left(-18\right)-\left(-27\right)-\left(+8\right)\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:$
$\left(4x^2-5x+3\right)+6$
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