$x'=x\cdot t$
$x^2+4\left(x+4\right)$
$\left(\frac{1}{5}a+\frac{2}{3}b-\frac{1}{6}c\right)^2$
$\lim_{n\to\infty}\left(\frac{\log^k\left(n\right)}{n^e}\right)$
$\frac{5x^3-3x^2+8x}{5x+2}$
$3d^{-4}\cdot3d^5$
$-3-6+5-2+5-4+1+5-8+9-7+2-9+7-1+8-5+4-4$
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