$\int\left(5-x^3\right)\left(x-3\right)^2dx$
$-6x+7\ge-17$
$z^2-\frac{5}{2}z\:$
$3n^4-n^3$
$x-3\le0$
$x^2+2x+7=0$
$17-18u=-18u+17$
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