$4x^3y^4-8x^2y^5$
$\int\left(x\right)\sqrt{3x+8}dx$
$\tan\left(x\right)+\cot\left(x\right)=\frac{\cos\left(x\right)}{\cos\left(x\right)}$
$( 2 x - 4 ) ^ { 2 }$
$\frac{d}{dx}xe^y-10y+3x=0$
$\left(2ab-c\right)^2$
$\sqrt[0]{-9}$
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