$\sqrt[3]{27a^3b^9c^{12}}$
$\left(4y+3\right)^0$
$\frac{\sqrt{7}}{\sqrt{7}}$
$\frac{d}{dx}\left(3^{-3x}\right)$
$5x^2y-2x-9;\:x=-3;\:y=1$
$\frac{dy}{dx}=\frac{x^3+y^3}{3xy^2}$
$36a^2+48ab+16b^2$
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