$\frac{\sec\left(x\right)-\cos\left(x\right)}{\sec\left(x\right)\cdot\tan\left(x\right)}$
$\int\frac{x-3}{\left(x-1\right)\left(x^2-1\right)}dx$
$\frac{d}{dx}\:4$
$y^4-6y^2z+9z^2$
$-3\sqrt[2]{81}$
$8\left(4^2\right)+-3\left(2\right)\left(-5\right)+-4\left(-3\right)$
$y^{\prime}=x\left(y^{2}+1\right)$
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