$\frac{-x^4+4x^2+2}{x-2}$
$y'=\frac{x^2}{y}$
$x^2+x+6$
$3\frac{-8}{-3}$
$x^3+4x^2-6+x$
$\left(\frac{7}{8}-x^4y^5\right)^3$
$\sqrt{y}dx+\left(x-2\right)dy=0$
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