$\left(-1\right).\left(-5\right).\left(-2\right).\left(-3\right)$
$-12\left(\frac{5}{6}x-5\right)+2x$
$x^2-25<0$
$\lim_{x\to0}\left(\frac{x}{cos\left(4x\right)-1}\right)$
$64x^6+16x^{24}+x^2$
$2\sin\left(7x\right)=-1$
$9m+12\cdot9m-12$
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