$\frac{3x^2+2x-4}{x^3-8}$
$1+2+6-60+3$
$\lim_{x\to1}\left(\frac{2x^2+7x-9}{3x^2-5x+2}\right)$
$\lim_{x\to\infty}\left(\ln\left(5x\right)e^{-7x^2}\right)$
$\left(-18\right)+\left(55\right)-\left(-15\right)$
$2x+9=37$
$21x\:\:\:\:\:=-63$
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