$\left(\left(-2\right)^5\right)-\left(-3\right)^3$
$\sqrt{4}-\sqrt{400}$
$\int\left(sin\left(3x\right)\sqrt{cos\left(3x\right)}\right)dx$
$x-3x+1+4x+5$
$-1+y^2-x+3y^2$
$16+6x-x^2$
$1-5\cos\left(x\right)=6$
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