$x\ge x-1$
$\frac{dy}{dx}=\frac{\left(x+y\right)^2-1}{x+y}-1$
$dy\:+\:\left(y-1\right)^2\cdot\:\:dx=0$
$\int\frac{x+1}{x^{2\:}-16}dx$
$\frac{8x^2-16x+6}{2x+1}$
$\frac{dy}{dx}=3y^{\frac{2}{\:3}}$
$y'=2x-3y+1,\:y\left(1\right)=5$
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