$\left(2a^3-4a\right)^3$
$\int\left(\frac{3}{z^2+2}\right)dx$
$\frac { 8 } { 1 x ^ { 3 } - 4 x ^ { 4 } }$
$\frac{6t^{2}-5t+5}{2t+3}$
$w\:-\:5=1$
$y'+2y=e^{-2x}$
$\frac{b^{2\:}-9b-7}{b^2}$
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