$\left(6x^2-1\right)^2$

$\lim_{x\to\infty}\left(x-3\right)$

$\tan\left(x\right)\tan^2\left(x\right)=\tan^3\left(x\right)$

$\frac{dy}{dx}\left(x^2\right)=6xy^{-1}$

$x^2+5x^3+3x^2-4x+7$

$\lim_{x\to0}\left(\frac{w^{2}}{\cos w-1}\right)$

$2\left(x-1\right)+8=6\left(2x-4\right)$