$8\frac{1}{2}+16\frac{1}{4}\cdot1$
$24-672:\left(-36-5.12\right)-15$
$\int\left(\frac{x^2-4x+3}{\sqrt{x}}\right)dx$
$\left(-122\right)-\left(52\right)-\left(10\right)$
$\frac{10^{-2}}{5^{-2}}$
$3tan^3x=tanx$
$x^2+29x-44=0$
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