$\int_4^5\left(\frac{x^3+4x}{x^4+8x^2+4}\right)dx$

$6\sec\left(x\right)+5=8\sec\left(x\right)+2$

$\frac{\left(256-y^8\right)}{\left(2+y\right)}$

$\lim_{x\to-2}\left(\frac{x^2-5}{x^2+4x+4}\right)$

$\left(z+6\right)\left(z-5\right)$

$\int\frac{\left(u^2+1\right)}{u^4+1}du$

$\frac{x^3+x^2+45x-2}{x-7}$