$a^2-4a+3$
$\left(y^{\frac{-1}{2}}\right)^4$
$6x^2-x-15=0$
$\int\frac{8x^3-8}{4x^3-x}dx$
$\frac{dy}{dx}=\frac{\left(-x-2y\right)}{2x+y}$
$\left(2y-z\right)^3$
$\int\frac{1}{2+x^2}dx$
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