$y^2+4y+3=0$
$\left(5x\:-\:y\right)^2$
$5-x=10$
$\left(4+h\right)^2$
$4x^{2\:}+12x$
$\cot^2\left(x\right)\left(2\sec^2\left(x\right)-2\right)$
$6x+5y-2z-4x-6y+5z$
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