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f(x)=(cos(2x)-2cos(4x))/(2sin(4x)+2sin(2x))−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

cos(2x)−2cos(4x)2sen(4x)+2sen(2x)\frac{cos\left(2x\right)-2cos\left(4x\right)}{2sen\left(4x\right)+2sen\left(2x\right)}

Step-by-step Solution

1

Factor the polynomial 2sin⁡(4x)+2sin⁡(2x)2\sin\left(4x\right)+2\sin\left(2x\right) by it's greatest common factor (GCF): 22

cos⁡(2x)−2cos⁡(4x)2(sin⁡(4x)+sin⁡(2x))\frac{\cos\left(2x\right)-2\cos\left(4x\right)}{2\left(\sin\left(4x\right)+\sin\left(2x\right)\right)}

Final answer to the exercise

cos⁡(2x)−2cos⁡(4x)2(sin⁡(4x)+sin⁡(2x))\frac{\cos\left(2x\right)-2\cos\left(4x\right)}{2\left(\sin\left(4x\right)+\sin\left(2x\right)\right)}

Try other ways to solve this exercise

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  • Product of Binomials with Common Term
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cos(2x)−2cos(4x)2sen(4x)+2sen(2x) 
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