$\frac{1}{4}b^3c-\frac{1}{6}b^3c+2b^3c-3b^{3c}$

$\tan\left(x\right)^4+2\tan\left(x\right)+1$

$\left(8x+1\right)\left(x-7\right)$

$\frac{8a^6}{2a^3}$

$703,972\:-\:25,31$

$\int\frac{2x^3-4x^2-x-3}{\left(x-3\right)\left(x+1\right)}dx$

$\left(\frac{x}{3}-\frac{y^2}{2}\right)^3$