$\lim_{x\to2}\left(\frac{1}{x^2-4}\right)^{\frac{1}{x+2}}$
$\frac{3}{x^2}+2$
$-5-17-13-4+1$
$\left(x-1\right)\left(x^2+4\right)$
$12.89+96.54+59.80$
$25^3-49$
$\sqrt[3]{1+26}$
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