2x3−4x2−2x+3−3\frac{2x^3-4x^2-2x+3}{-3}−32x3−4x2−2x+3
∫(36−(6sin(x))2)dx\int\left(\sqrt{36-\left(6\sin\left(x\right)\right)^2}\right)dx∫(36−(6sin(x))2)dx
(4a−5b−8c)−(3b−c+2d−6b)+(4a−5b+4c−3d)\left(4a-5b-8c\right)-\left(3b-c+2d-6b\right)+\left(4a-5b+4c-3d\right)(4a−5b−8c)−(3b−c+2d−6b)+(4a−5b+4c−3d)
∫a1(1(2x−3)2)dx\int_a^1\left(\frac{1}{\left(2x-3\right)^2}\right)dx∫a1((2x−3)21)dx
y+xy=x2y′y+xy=x^2y'y+xy=x2y′
∫ x2(x3+1)dx\int\:\:x^2\left(x^3+1\right)dx∫x2(x3+1)dx
3x4−x2+xx3−2x\frac{3x^4-x^2+x}{x^3-2x}x3−2x3x4−x2+x
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