$\left(4^3\cdot4\cdot4\right)$
$\int\frac{4x^4-18x^2+6}{2x^3-3x}dx$
$24x^2\left(x-3\right)+36x^3\left(x-3\right)$
$\lim_{x\to1}\left(\frac{\left(x-1\right)^2}{x-e^{x-1}}\right)$
$43.00+16.00+7.00+1.8$
$7x-8+-5x-6$
$\lim_{x\to\infty}\left(\frac{\sqrt{9x^6-x}}{x^3+3}\right)$
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