$\lim_{x\to-3}\left(\frac{x+1}{x+3}\right)$
$64x^2-16$
$\int\left(\frac{sec^2\left(3-\sqrt{x}\right)}{\sqrt{x}}\right)dx$
$\ln\left(6t+5\right)=-5$
$\frac{dy}{dx}=\frac{\left(x-1\right)y^6}{x^2\left(2y^3-y\right)}$
$73y+43y+24u+33$
$-5x^2+22x-8$
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