$2x-3=5$
$\frac{dx}{dt}=5-6x+x^2$
$x^3-27x+54$
$\frac{\left(6\cdot\:\:10^6\right)^4}{\:\left(8\cdot\:\:10^3\right)^2}$
$f\left(x\right)=\frac{x}{\left(1+x\right)^2}$
$\lim_{x\to0}\left(\frac{x-arcsinx}{sin^3x}\right)$
$5cosx+6=10cosx+5$
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