$\frac{d^2}{dx^2}\left(\frac{2}{\left(x^2-4\right)}\right)$
$\sqrt{\sin^2x+cos^2x}=\:\sin\left(x\right)\:+\:\cos\left(x\right)$
$x^6+1x^3-42$
$9^2-3-5$
$3-\frac{2}{3}x=1$
$-5x^2y^2-1+x;\:x=-3y=-1$
$2^{-1}\left(2^4\right)$
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