$3x\left(3x-5\right)$
$\frac{1}{1+csc\left(x\right)}+tan^2\left(x\right)$
$-3a+5b+8b-14b+19b-3a-a$
$\frac{d}{dx}x+4y=1$
$\frac{\sqrt[5]{x^2}}{4+3x^2}$
$\left(y^3-7y\right)\left(-8+y^3\right)$
$5x^3-2x^2\left(3x^3-4x\right)$
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