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Exercise

$\frac{6xy+3x^2y}{x^2-4}\cdot\frac{x^2-3x+2}{12xy}$

Step-by-step Solution

1

Multiplying fractions $\frac{6xy+3x^2y}{x^2-4} \times \frac{x^2-3x+2}{12xy}$

$\frac{\left(6xy+3x^2y\right)\left(x^2-3x+2\right)}{12\left(x^2-4\right)xy}$

Final answer to the exercise

$\frac{\left(6xy+3x^2y\right)\left(x^2-3x+2\right)}{12\left(x^2-4\right)xy}$

Try other ways to solve this exercise

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Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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