$\int\frac{\left(6\right)x}{\sqrt{9x^2-5}}dx$
$4a\:-\:6b-2a\:+6b$
$16x^2-49$
$\int\sqrt{1+16x^2}dx$
$\frac{1}{1+\sin\left(1\right)}=\left(\sec\left(1\right)-\tan\left(1\right)\right)\sec\left(1\right)$
$-6\sqrt{3}-4\sqrt{3}$
$\left(8c^2-3\right)^3$
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