$\frac{1}{x+3}=\frac{1}{x}-\frac{1}{6}$
$\lim_{x\to4}\left(\frac{4-x^2}{sen\left(\pi x\right)}\right)$
$-4x\:-\:11x\:=\:15$
$\frac{3x^2+4x+5}{x+5}$
$8x^3-48x^2y+96xy^2-64y^3$
$8x^5-12x^3+4x^2$
$4x^2+24x+27$
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